What is the mole-mole ratio (conversion factor) for Cal2 (Calcium iodide) to Ca3(PO4)2 (calcium Phosphate)?

3 Cal2 (aq) + 2 (NH4)3PO4 (aq) –> Ca3(PO4)2 (s) + 6 NH4I (aq)

a). What is the mole-mole ratio (conversion factor) for Cal2 (Calcium iodide) to Ca3(PO4)2 (calcium Phosphate)?

B). If you start with 16.35 g of Cal2, how much (in grams) solid Ca3 (PO4) is expected (Theoretical yield)?

c). If you run the experiment and isolate 4.77 g of Ca3(PO4)2, what is your percent yield?

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